☰ अधिक माहितीसाठी येथे क्लीक करा

Question 1:

At a rate of 10 p.c.p.a., what would be the interest for one year on  rupees 6000?

Given:
Principal (P) = 6000 rupees
Rate of interest (R) = 10%
Time (T) = 1 year
Now, Interest = $\frac{P×R×T}{100}$
$=\frac{6000×10×1}{100}\phantom{\rule{0ex}{0ex}}=\frac{60000}{100}$
= 600 rupees
Hence,  the interest for one year would be 600 rupees.

Question 2:

Mahesh deposited rupees 8650 in a bank at a rate of 6 p.c.p.a. How much money will he get at the end of the year in all?

Given:
Principal (P) = 8650 rupees
Rate of interest (R) = 6%
Time (T) = 1 year
Now, Interest = $\frac{P×R×T}{100}$
$=\frac{8650×6×1}{100}\phantom{\rule{0ex}{0ex}}=\frac{51900}{100}$
= 519 rupees
Therfore, Amount = Principal + Interest
= 8650 + 519
= 9169
Hence, Mahesh will get 9169 rupees at the end of the year in all.

Question 3:

Ahmed Chacha borrowed rupees 25000 at 12 p.c.p.a. for a year. What amount will he have to return to the bank at the end of the year?

Given:
Principal (P) = 25000 rupees
Rate of interest (R) = 12%
Time (T) = 1 year
Now, Interest = $\frac{P×R×T}{100}$
$=\frac{25000×12×1}{100}\phantom{\rule{0ex}{0ex}}=\frac{300000}{100}$
= 3000 rupees
Therfore, Amount = Principal + Interest
= 25000 + 3000
= 28000 rupees
Hence, Ahmed Chacha will have to return 28000 rupees to the bank at the end of the year.

Question 4:

Kisanrao wanted to make a pond in his field. He borrowed rupees 35250 from a bank at an interest rate of 6 p.c.p.a. How much interest will he have to pay to the bank at the end of the year ?

Now, Interest = $\frac{P×R×T}{100}$
$=\frac{35250×6×1}{100}\phantom{\rule{0ex}{0ex}}=\frac{211500}{100}$
Std 6 th Mathematics- 14. Banks and Simple Interest Reviewed by Amol Uge on January 09, 2019 Rating: 5